1.Oracle:
- select * from ( select row_.*, rownum rownum_ from ( query_SQL ) row_ where rownum =< max) where rownum_ >= min
2.SQL Server:
- select top @pagesize * from tablename where id not in (select top @pagesize*(@page-1) id from tablename order by id) order by id
3.MySQL
- select * from tablename limit position, counter
4.DB2
- select * from (select *,rownumber() as ROW_NEXT from tablename) where ROW_NEXT between min and max
1.分页方案一：(利用Not In和SELECT TOP分页)效率次之
语句形式：
- SELECT TOP 10 * FROM TestTable
- WHERE(ID NOT IN (SELECT TOP 20 id FROM TestTable ORDERBY id)) ORDERBYID
- SELECT TOP 页大小 * FROM TestTable
- WHERE( ID NOT IN (SELECT TOP 每页大小-1*待查询页数-1 id FROM 表 ORDERBY id)) ORDERBYID
思路:先查询出待查询页之前的全部条数的id,查询ID不在这些ID中的指定数量条数
2.分页方案二：(利用ID大于多少和SELECT TOP分页)效率最高
语句形式：
- SELECT TOP 10 * FROM TestTable
- WHERE(ID>(SELECT MAX(id) FROM(SELECT TOP20 id FROM TestTable ORDERBYid)AS T))ORDERBY ID
- SELECT TOP 页大小* FROM TestTable
- WHERE(ID>(SELECT MAX(id) FROM(SELECT TOP 每页大小*待查询页数-1 id FROM 表 ORDERBY id)AS T)) ORDERBY ID
思路:先获得待查询页的之前全部条数id,获得它们当中最大的ID号,以此最大ID号为标志,查找比这个ID号大的指定条数
3.分页方案三：
- SELECT TOP PageSize * FROM(SELECT TOP nPage*PageSize * from YOURTABLE order by id)as a order by id desc
- SELECT TOP 每页条数 * FROM (SELECT TOP 待查询页*每页条数) * from YOURTABLE order by id)as a order by id desc
思路:先正排序查询出待查询页之前(包括当前页)的全部条数,然后将其倒排序,取指定条数
原文链接：http://www.cnblogs.com/yongle_tianya/archive/2011/08/02/2125197.html
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