sql server数据库的列信息查看的方法是最常用的操作方法之一，本文为您详述了怎么使用T-Sql语句， 在sql server 2005中提取一个数据表的列的详细信息的方法，并附sql server的开发实例，供您参考，希望对您有所帮助。
下面介绍的是名为sp_GetColumnsInfo的存储过程，示例中使用了微软提供的AdventureWorks数据库。
USE AdventureWorks;
--Method I: Using System Store Procedure
EXEC SP_COLUMNS @table_name = N'Employee'
GO
--Method II: Using T-Sql Statement
--If existed, delete the store procedure
IF EXISTS (
SELECT *
FROM INFORMATION_SCHEMA.ROUTINES
WHERE SPECIFIC_SCHEMA = N'dbo'
AND SPECIFIC_NAME = N'sp_GetColumnsInfo'
)
DROP PROCEDURE [dbo].sp_GetColumnsInfo
GO
--create store procedure, two parameters schema name and table name
CREATE PROCEDURE sp_GetColumnsInfo
@schema NVARCHAR(100),
@tablename NVARCHAR(100)
AS
BEGIN#p#
SELECT
[columns].NAME AS [Name],
[usertype].NAME AS [DataType],
ISNULL([basetype].NAME, N'') AS [SystemType],
CAST(CASE WHEN [basetype].NAME IN (N'nchar', N'nvarchar') AND [columns].max_length <> -1 THEN
[columns].max_length/2 ELSE [columns].max_length END AS INT) AS [Length],
CAST([columns].PRECISION AS INT) AS [NumericPrecision]
FROM
SYS.TABLES AS [table]
INNER JOIN SYS.ALL_COLUMNS AS [columns] ON [columns].OBJECT_ID=[table].OBJECT_ID
LEFT OUTER JOIN SYS.TYPES AS [usertype] ON [usertype].user_type_id = [columns].user_type_id
LEFT OUTER JOIN SYS.TYPES AS [basetype] ON [basetype].user_type_id = [columns].system_type_id and [basetype].user_type_id = [basetype].system_type_id
WHERE
([table].NAME=@tablename and SCHEMA_NAME([table].schema_id)=@schema)
ORDER BY
[columns].column_id ASC
END
EXEC sp_GetColumnsInfo @schema = N'HumanResources', @tablename = N'Employee'
结果显示
(16 row(s) affected)
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