Python 拼写检查在使用的时候有些问题一直在困扰着我们。其实只有不断的学习才能更好的使用这门语言。这几天在翻旧代码时发现以前写的注释部分有很多单词拼写错误，这些单词错得不算离谱，应该可以用工具自动纠错绝大部分。
用 Python 拼写检查脚本很容易，如果能很好利用 aspell/ispell 这些现成的小工具就更简单了。
Google 大牛 Peter Norvig 写了一篇 How to Write a Spelling Corrector 很值得一看，大牛就是大牛，21行 Python拼写检查问题，而且还不用外部工具，只需要事先读入一个词典文件。本文程序的 edits1 函数就是从牛人家那里 copy 的。
#!/usr/bin/python
# A simple spell checker
# written by http://www.vpsee.com
import os, sys, subprocess, signal
alphabet = 'abcdefghijklmnopqrstuvwxyz'
def found(word, args, cwd = None, shell = True):
child = subprocess.Popen(args,
shellshell = shell,
stdin = subprocess.PIPE,
stdout = subprocess.PIPE,
cwdcwd = cwd,
universal_newlines = True)
child.stdout.readline()
(stdout, stderr) = child.communicate(word)
if ": " in stdout:
# remove \n\n
stdoutstdout = stdout.rstrip("\n")
# remove left part until :
left, candidates = stdout.split(": ", 1)
candidatescandidates = candidates.split(", ")
# making an error on the first letter of a word is less
# probable, so we remove those candidates and append them
# to the tail of queue, make them less priority
for item in candidates:
if item[0] != word[0]:
candidates.remove(item)
candidates.append(item)
return candidates
else:
return None
# copy from http://norvig.com/spell-correct.html
def edits1(word):
n = len(word)
return set([word[0:i]+word[i+1:] for i in range(n)] +
[word[0:i]+word[i+1]+word[i]+word[i+2:] for i in range(n-1)] +
[word[0:i]+c+word[i+1:] for i in range(n) for c in alphabet] +
[word[0:i]+c+word[i:] for i in range(n+1) for c in alphabet])
def correct(word):
candidates1 = found(word, 'aspell -a')
if not candidates1:
print "no suggestion"
return
candidates2 = edits1(word)
candidates = []
for word in candidates1:
if word in candidates2:
candidates.append(word)
if not candidates:
print "suggestion: %s" % candidates1[0]
else:
print "suggestion: %s" % max(candidates)
def signal_handler(signal, frame):
sys.exit(0)
if __name__ == '__main__':
signal.signal(signal.SIGINT, signal_handler)
while True:
input = raw_input()
correct(input)
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以上就是对Python 拼写检查的相关解决方案。
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